TypeError: 'float' object not callable in Python

Question

I'm pretty new to coding so this may be a silly problem but when I try to run my programme I get the error mentioned in the title. The bit of code which seems to be the problem is this:

def branch(replicas):
    ER = d * 0.5 * w
    N0 = len(replicas)
    newReplicas = []   ##### Error on this line 

    for j in range( len(replicas) ):

        replica = replicas[j]

        r2 = 0

        for x in replica:

            r2 += x * x

            V = 0.5 * mass * w**2 * r2

            W = exp(-(V - ER) / rootT)

            mn = int(W + random.uniform(0,1))

            if mn >= 3:

                newReplicas.append( replica )

                newReplicas.append( replica )

                newReplicas.append( replica )

            elif mn == 2:    

                newReplicas.append( replica )

                newReplicas.append( replica )

            elif mn == 1:

                newReplicas.append( replica )

    replicas = newReplicas
    N1 = len(replicas)
    ER = ER + ((hbar/deltaT)(1-(N1/N0)))

Any help would be appreciated. Thanks in advance!

What is your last line supposed to do? You have a close paren followed by an open paren. — Daniel Roseman
– Daniel Roseman, Commented Oct 29, 2015 at 21:11
The last line is supposed to modify a variable ER which I defined in a line before the block that you can see here. Thanks for pointing that out, I've fixed it and no longer get the error! — Hazwell
– Hazwell, Commented Oct 29, 2015 at 21:17
I would hazard to guess that a multiplication goes there, between the closed and open parenthesis. Otherwise, that would be where the TypeError is generated. — Erik
– Erik, Commented Oct 29, 2015 at 21:17
There are many variables that defined in the global context: d, w, mass. Not the problem, but not good practice either. — Erik
– Erik, Commented Oct 29, 2015 at 21:19
Those variables are all input values which I need to use in various parts of the programme. What is bad about defining things in the global context? — Hazwell
– Hazwell, Commented Oct 29, 2015 at 21:26

James Hurford · Accepted Answer · 2015-10-29 22:27:33Z

1

I think your problem lies here

ER = ER + ((hbar/deltaT)(1-(N1/N0)))

I think what you're after is this

ER = ER + ((hbar/deltaT)*(1-(N1/N0)))

What Python thinks you want is to call a object of the value returned by evaluating

hbar/deltaT

So if

hbar = 2.0
deltaT = 1.0

then it thinks your trying to call the float object it creates, as in this case it would be a float object of the value 2.0, with the parameter of the result of evaluating

1-(N1/N0)

Since float objects are not callable, this doesn't work, and throws and exception.

Essentially you can fix this by putting the multiplication operator between

(hbar/deltaT)

and

(1-(N1/N0))

ending up with

((hbar/deltaT)*(1-(N1/N0)))

Which is what I think you're trying to do. Unless you didn't want to do multiplication

edited Oct 29, 2015 at 22:27

answered Oct 29, 2015 at 22:18

James Hurford

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