About Java input string filter

Question

I have a very simple question about JAVA string filter I to want input this command to console.

add 100@10

which means execute add method input arguments 100 and 10 respectively.

I used

String[] s = str.split("@");

String a = s[0];// here can get 100

String b=s1];// get can get 10

I have two questions

first is how to do delete the at (@) character before put it to string.split()
second can anyone can provide some better solution to handle this kind of input ?

such as

add 1000@10   //only add,1000,10 need to take 
times 1000@10  //only add,1000,10 need to take

if you remove the @ character, how do you want to split your command? — messerbill
– messerbill, Commented Nov 11, 2015 at 15:51
you can see my command is add 1000@10,which means 1000+10 i want get the three arguments in the string seperately ,could be [add][1000][10] — user2953788
– user2953788, Commented Nov 11, 2015 at 15:54
and apples are not cherries....he posted java code and tagged the question as "Java" - whats the problem — messerbill
– messerbill, Commented Nov 11, 2015 at 15:56

ergonaut · Accepted Answer · 2015-11-11 16:09:04Z

3

You can split on multiple tokens because it's a regex parameter:

String a[] = "aadd 100@200".split("[ @]");

returns ["aadd", "100", "200"]

Then you can do

String command = a[0];
String operand1 =  a[1];
String operand2 = a[2];

answered Nov 11, 2015 at 15:57

ergonaut

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Comments

messerbill · Accepted Answer · 2015-11-11 16:00:40Z

1

not as sexy as ergonaut's solution, but you also can use two splits:

String[] arr1 = "add 100@10".split(" ");
String[] arr2 = arr1[1].split("@");
String[] result = [arr1[0], arr2[0], arr2[1]];

should be

["add","100","10"]; // this is result

greetings

answered Nov 11, 2015 at 16:00

messerbill

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