linux-Ruby - run a ruby application as a command

Question

I want to run a lib of ruby files from the command prompt from anywhere in a command line. I have the Main.rb program which instantiates classes from other ruby files.

I store the class path of my lib in the .zshrc. Then I run the Main.rb but it is not able to load the required ruby files (files in my lib folder) and throws this error:

`require': no such file to load -- Data.rb (LoadError)

How can I tackle this issue? I just need a neat command to be run on shell and throw results on console.

Please help.

Try putting this at the top of Main.rb: $: << '.' unless $:.include? '.' — Adrian
– Adrian, Commented Aug 1, 2010 at 18:48

Seamus Campbell · Accepted Answer · 2010-08-01 18:50:10Z

2

Ruby searches the directories in the $LOAD_PATH variable to try to find files you import with the 'require' statement. You have a few options:

move your files to a directory in the $LOAD_PATH list
give Ruby the path to your libraries in your require statement:

require '/home/mydir/myproject/lib/Data.rb'
modify $LOAD_PATH in Main.rb to include your lib directory
pass Ruby a command-line argument adding your lib directory to $LOAD_PATH with the -I option:

ruby -I/home/mydir/myproject/lib Main.rb

answered Aug 1, 2010 at 18:50

Seamus Campbell

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1 Comment

user384070 Over a year ago

Hey $: << '.' unless $:.include? '.' doesnot work plus how can I just use it as a normal command say test or just Main without any .rb thing... I m planning to use the third option above but still dono how to include this in my code.

rogerdpack · Accepted Answer · 2010-08-03 16:43:51Z

0

Typically you'll need to change your

 require 'abc'

to a relative path, like

 require File.dirname(__FILE__) + "/abc"

or use (my) require_relative on 1.9

 require_relative 'abc'

GL. -r

answered Aug 3, 2010 at 16:43

rogerdpack

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