Laravel parsing json output correctly

Question

i am using this code in laravel .

 $user_detail = \App\Userpacakage::with('user.pacakage')->where('pacakage_id', '=', 1)->get(); //->lists('nombre', 'id')
        return response()->json($user_detail);

this is my json output ->

[{"id":1,"user_id":1,"pacakage_id":1,"transaction_id":"jfjkgjgjkhkjkg55rtf","created_at":"-0001-11-30 00:00:00","updated_at":"-0001-11-30 00:00:00","user":{"id":1,"name":"omsun","email":"[email protected]","contact":2147483647,"regkey":"","created_at":"2015-11-21 01:18:33","updated_at":"2015-11-21 01:18:33","pacakage":[{"id":1,"title":"dsagdjas","description":"<p>\r\n\tsamndbmasndmas,<\/p>\r\n","tab_id":0,"from":"11\/27\/2015","to":"12\/03\/2015","days":22,"unlimited":0,"criteria":1,"category_id":1,"subcategory_id":0,"subject_id":0,"price":2432,"created_at":"2015-11-21 19:07:10","updated_at":"2015-11-21 19:07:10","pivot":{"user_id":1,"pacakage_id":1}}]}}]

using jquery i am using this code to fetch user details

$.get('api/classallocation?pacakage_id=' + pacakage_id, function (data) {

                    console.log(data);
                     $.each(data, function (i, user) {

                         console.log(user.name));
                     });

i want to know how to fetch the pacakage details in jquery ..like pacakage title ,price.

what exactly is your question? please add more information on what input you give and the output you get, and what your code looks like. — EkcenierK
– EkcenierK, Commented Nov 22, 2015 at 0:18
i am laravel $user_detail = \App\Userpacakage::with('user.pacakage')->where('pacakage_id', '=', 1)->get(); //->lists('nombre', 'id'); return response()->json($user_detail); — Omsun Kumar
– Omsun Kumar, Commented Nov 22, 2015 at 0:36
And what is the error or problem you have with the parsing? Please update your question. — EkcenierK
– EkcenierK, Commented Nov 22, 2015 at 8:42

Sudarshan · Accepted Answer · 2017-11-15 20:11:13Z

1

$.get('api/classallocation?pacakage_id=' + pacakage_id, function (data) {
   console.log(data);
   $.each(data, function (i, user) {
   console.log(user.pacakage[0].title));
});

answered Nov 15, 2017 at 20:11

Sudarshan

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