How to pass bash variable to a string?

Question

I am doing everything in a bash file. I am grabbing to variables from a parameter:

brand="$1"
email="$2"

Afterwards, I want to include on of them inside of a string:

 cd /etc/nginx/sites-available/

 echo 'server {
    listen       80;
    server_name  $brand.mydomain.com;
    root         /srv/www/clients/$brand/soon;
 }' >> default

But it echo's $brand.mydomain.com. How to echo the actual value which I am passing as parameter?

Use double quotes instead of single quote in echo.

Diego Sevilla
– Diego Sevilla

2016-01-23 21:26:03 +00:00
Commented Jan 23, 2016 at 21:26 — Diego Sevilla
– Diego Sevilla, Commented Jan 23, 2016 at 21:26

Rumbleweed · Accepted Answer · 2016-01-23 21:28:51Z

1

Single quotes don't allow for expansion of anything. Double quotes allow for expansion of variable, but you best enclose the name with parenthesis as shown.

echo "server {
    listen       80;
    server_name  ${brand}.mydomain.com;
    root         /srv/www/clients/${brand}/soon;
}" >> default

answered Jan 23, 2016 at 21:28

Rumbleweed

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1 Comment

cdarke Over a year ago

No need for the braces here. The . and the / characters are not valid variable name characters so they terminate the name. The practice of enclosing with braces is often needed in csh where the expansions are different, but only in bash when surrounded by alphanumerics or underscores.

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