not enough argument, self-defined function in matlab

Question

I am a newbie of matlab and am trying to define a pretty complex function to plot it. The content of file is following:

function [res] = distribution (input)
a = factorial(30)
b = factorial(input) * factorial(30-input)
c = power(0.05, input)
d = power(0.95, 30-input)

a/b*c*d
end

in the file named distribution with .m extension. But when I run it error returns: "Error using distribution (line 4). Not enough input arguments."

I read through the "Getting Started" and find no solution. Does anyone have suggestions on this?

how do you call your distribution function ?

Derlin
– Derlin

2016-02-21 07:57:27 +00:00
Commented Feb 21, 2016 at 7:57 — Derlin
– Derlin, Commented Feb 21, 2016 at 7:57

dfrib · Accepted Answer · 2016-02-21 08:29:42Z

3

The name of the single argument to your function distribution(..), namely argument input, conflicts with the existing native input command of Matlab,

input: Prompt for user input.

...
x = input(prompt)

Try choosing a different name of this argument (in example below: foo), and also remember to return your result by assigning it to the return variable res:

function res = distribution (foo)
    a = factorial(30);
    b = factorial(foo) * factorial(30-foo);
    c = power(0.05, foo);
    d = power(0.95, 30-foo);

    res = a/b*c*d; % <--- note, return parameter assignment
end

answered Feb 21, 2016 at 8:29

dfrib

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