I'm using Python 2.7.
class Client():
def __init__(self, host, server_port):
"""
This method is run when creating a new Client object
"""
self.host = 'localhost'
self.server_Port = 1337
# Set up the socket connection to the server
self.connection = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
self.receiver = None
self.myParser = MessageParser()
# TODO: Finish init process with necessary code
self.run()
def run(self):
self.connection.connect((self.host, self.server_Port))
self.receiver = MessageReceiver(self, self.connection) #On this line, a MessageReceiver object is instantiated.
self.take_input()
class MessageReceiver(Thread):
def __init__(self, client, connection):
super(MessageReceiver, self).__init__()
self.myClient = client
self.connection = connection
self.daemon = True
self.run()
def run(self):
self.myClient.receive_message(self.connection.recv(1024)) #This line blocks further progress in the code.
When the run-method in the Client object instantiates a MessageReceiver object, I want the next line of code in Client to be executed immediately, without waiting for an exit code from MessageReceiver. Is there a way to do this?
