problem accessing to a variable in object

Question

Edit: this is part of main function to call the grab function:

  $video['type']          = $videoProvider;
  $video['id']          = $videoIds;
  $video['title']          = $this->grab_title_from_curl($data);

I have this little function to parse title from html via curl, it works.

  private function grab_title_from_curl ($pull){
    preg_match("/<meta name=\"title\" content=\"(.*?)\"/", $pull,$data) ;
    return $data;
  }

and shows me this:

Array
(
    [type] => yahoo
    [id] => 613478/2923165
    [title] => Array
        (
            [0] =>  EXELENTE TIRO DE ARCO!!
        )
)

I need to [title] directly gets the value of [0] in the array. like: [title] => EXELENTE TIRO DE ARCO!!

second edit:

for some reason the code breaks when i use JoostK's code: pastie.org

sorry for my bad english!

SOLVED: instead of preg_match("/?)\"/", $pull,$data); preg_match('/?)\"/', $pull,$data) ;

The array you show can't be the $data array. Easiest but not most elegant way would be to use $array['title']=$array['title'][0]; There may be better ways to do it, but then we need a bit more code. — Joost
– Joost, Commented Sep 1, 2010 at 23:07
don't works! i've tried a lot of ways but i cant make it work. — greenbandit
– greenbandit, Commented Sep 1, 2010 at 23:18

Joost · Accepted Answer · 2010-09-01 23:49:44Z

1

Based on your edit, this should work:

private function grab_title_from_curl ($pull){
    $data = array();
    preg_match("/<meta name=\"title\" content=\"(.*?)\"/", $pull, &$data);
    return $data[0];
}

edited Sep 1, 2010 at 23:49

answered Sep 1, 2010 at 23:18

Joost

10.4k4 gold badges59 silver badges62 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

greenbandit Over a year ago

don't works, and also breaks the array: <code> Array ( [type] => yahoo [id] => 613478/2923165 [title] => </code>

greenbandit Over a year ago

it breaks again! any new idea?

Rob Olmos · Accepted Answer · 2010-09-01 23:04:51Z

0

Use a temporary variable to hold the matches:

private function grab_title_from_curl ($pull){
    $matches = array();
    preg_match("/<meta name=\"title\" content=\"(.*?)\"/", $pull, $matches) ;
    $data['title'] = $matches[0];
    return $data;
}

answered Sep 1, 2010 at 23:04

Rob Olmos

2,43216 silver badges24 bronze badges

4 Comments

greenbandit Over a year ago

don't works shows me an empty array, but if delete the [0] part i got: [title] => Array ( [title] => Array ( [0] => EXELENTE TIRO DE ARCO!!

Rob Olmos Over a year ago

Based on your new edit I see how you're doing it. In that case JoostK's answer above should be correct. It's good practice to declare your variables before using them.

Rob Olmos Over a year ago

greenbandit: Try removing the ampersand (&) before the $data variable in JoostK's code above.

Joost Over a year ago

The ampersand is there because I pass the variable by reference. In PHP it doesn't matter (as far as I know) whether you do it or not, however now I can clearly see that the variable is a reference, not having to look it up in the documentation.

Collectives™ on Stack Overflow

problem accessing to a variable in object

2 Answers 2

2 Comments

4 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

4 Comments

Your Answer

Sign up or log in

Post as a guest

Related