Delete element from array when a condition match in shell script

Question

I am iterating through the array in shell script and when condition matches i.e. if found 'b' want to delete that element from the array. I am not using the index position to iterate through. My array has values (a b c)

My code is

for h in $Arr
do 
    echo -e "Value of current element $h.\n"

    if [ $h == "b" ]
    then
        echo -e "Delete it\n"

    else
        echo -e "Stay here\n"
    fi
done

How can I delete 'b' when condition matches so that when I print my array it should print (a c) ??

J. Chomel · Accepted Answer · 2016-04-07 13:06:48Z

1

You could build a temp array Brr with the accepted values, then assign Arrwith its value?

Arr=" a b c"
Brr=""
for h in $Arr
do
  echo -e "Value of current element $h.\n"
  if [ $h == "b" ]
  then
    echo -e "Delete it\n"
    #do not add it to Brr
  else
    echo -e "Stay here\n"
    # add it to Brr the temp array
    Brr="${Brr} $h"
  fi
done
Arr="${Brr}"
echo $Arr

answered Apr 7, 2016 at 13:06

J. Chomel

8,44215 gold badges44 silver badges72 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Delete element from array when a condition match in shell script

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related