Json Decode returning NULL

Question

I am trying to decode json into array in PHP.But My json is like

string(307) " string(290) "{"id":"1","name":"test name","rowno":"0","note":"test notes","created_date":"2016-05-01","updated_date":"2016-05-12 05:08:05"}" "

string within a string!! How to convert it into array.

This is a var_dump() of the json. Where is this json being produced? Show the code that generates it. — Darren
– Darren, Commented May 13, 2016 at 3:53

Darren · Accepted Answer · 2016-05-13 03:59:52Z

3

This looks like you're trying to decode (or trying to output) the data with var_dump(). That isn't the function you require; what you require is json_decode():

$data = json_decode($json);

If that isn't the issue, and you're actually receiving the data as above then you'll have to strip it out - most likely using a regex like the following:

$s = 'string(307) " string(290) "{"id":"1","name":"test name","rowno":"0","note":"test notes","created_date":"2016-05-01","updated_date":"2016-05-12 05:08:05"}" "';

preg_match('/\{(.*)\}/', $s, $matches);

print_r($matches);

Which would return your json:

Array
(
    [0] => {"id":"1","name":"test name","rowno":"0","note":"test notes","created_date":"2016-05-01","updated_date":"2016-05-12 05:08:05"}
    [1] => "id":"1","name":"test name","rowno":"0","note":"test notes","created_date":"2016-05-01","updated_date":"2016-05-12 05:08:05"
)

Thus allowing you to decode it properly within $matches.

Regex is a beast to me so I'll try explain as best as possible what the expression is doing:

\{ matches the first open {
(.*) matches any character inbetween
\} matches the closing }

edited May 13, 2016 at 3:59

answered May 13, 2016 at 3:54

Darren

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2 Comments

Shashikala Over a year ago

Yes you are right.The problem is am using var_dump() instead of echo.I changed it and it is working fine.Thank you :-)

Jigar7521 Over a year ago

After a lot RND, this is the answer which work for me and making sans.

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