ajax multiple data sent parameters php

Question

whats wrong with this?

EDIT:

 $check = $row['publish'] == 1 ? 'true' : 'false';

It works when I want to unpublished, but if the checkbox is empty I cannot publised.

 OnClick="doAction(<?php echo $check;?>, <?php echo $id;?>);"



function doAction(check,id){
 $.ajax({

      type: "GET",
      url: "test.php",
      data: "check=" + check + "&id=" + id,
      success: function(msg){
                 alert( "Data Saved: " + msg );
               }
 });
}

and the file test.php:

$id = $_GET['id'];
        $check = $_GET['check'];
        if ($check == "false"){
            $query = mysql_query("update article set publish = 1 where id =" . $id);
            echo "Published";
        }
        else {
            $query = mysql_query("update article set publish = 0 where id =" . $id);
            echo "Unpublished";
        }

I cannot display the id in the test.php file.it gives me nothing. But in the doAction parameters are(.., id) so it's been sent but I don t receive it in the ajax call and then in file. Why?

Assigning $check as checked or unchecked. And, In test.php, condition in if is $check == "false". Why? — Nana Partykar
– Nana Partykar, Commented Jul 27, 2016 at 8:35
Try out this: $.ajax({ type: "GET", url: "test.php?check="+ check + "&id = " + id, success: function(msg){ alert( "Data Saved: " + msg ); } }); — Pankaj
– Pankaj, Commented Jul 27, 2016 at 8:37
then how to assign the $check? in test.php if I write echo $check it gives me the( id, false) if I unpublished. but when i click the checkbox to published only it checks but doesn;t return anything, neither id or check status. — chi
– chi, Commented Jul 27, 2016 at 8:39
the problem is with the data you are passing to your function doAction(check, id). check that first! — devasia2112
– devasia2112, Commented Jul 27, 2016 at 9:00

rad11 · Accepted Answer · 2016-07-27 08:38:17Z

1

Try change:

data: "check=" + check + "&id = " + id,

To:

data: "check=" + check + "&id=" + id,

And you should define what will be response HTML , JSON etc. use for this example:

dataType: "JSON"

answered Jul 27, 2016 at 8:38

rad11

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6 Comments

chi Over a year ago

doesn't work. the problem I think is with $check = $row['publish'] == 1 ? 'checked' : 'unchecked';. It doesn't work for unchecked.

rad11 Over a year ago

Edit your code to current revision. And try change $row['publish'] == 1 ? 'checked' : 'unchecked'; to $row['publish'] == 1 ? 'true' : 'false'; because you try check that value not checked or unchecked. Pass to html

rad11 Over a year ago

Show what u got in var_dump($_GET["id"]), var_dump($_GET["check"]); before if

chi Over a year ago

now it works, it really works but it doesn;t remain in the checkbox the values. I mean if it's 1 in db it's not checked.

rad11 Over a year ago

So change $row['publish'] == 1 ? 'true' : 'false'; to $row['publish'] == 1 ? 'false' : 'true'; I do not know what about you in the database represents the value 1 is you need to set an appropriate value to Your code to run what I gave must act

|

Benaya Paul · Accepted Answer · 2016-07-27 09:30:33Z

0

If you are passing the value in arguments use below code.

 OnClick="doAction('<?php echo $check;?>', '<?php echo $id;?>');"

answered Jul 27, 2016 at 9:30

Benaya Paul

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