Laravel double validation regex not working

Question

I'm trying to validate a double with two decimals but I can't achieve that. This is the regex and the errors I tryied and I got:

First try:

$validation = ['price' => 'regex:[0-9]+(\.[0-9][0-9]?)?'];

Error:

preg_match(): Unknown modifier '+'

Second try:

$validation = ['price' => 'regex:[0-9]+(\.[0-9][0-9]?)?'];

Error:

preg_match(): Delimiter must not be alphanumeric or backslash

Third try:

$validation = ['price' => 'regex:\d+(\.\d{2})?|\.\d{2}'];

Error:

preg_match(): Delimiter must not be alphanumeric or backslash

I got all the regex from this question: Simple regular expression for a decimal with a precision of 2

What am I doing wrong? Or there is any other way to validate a double with two decimals in Laravel?

Try $validation = ['price' => 'regex:/[0-9]+(\.[0-9][0-9]?)?/']; — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Aug 14, 2016 at 22:24
@WiktorStribiżew Thank you it works, but is it any way to prevent more than two decimals? — pableiros
– pableiros, Commented Aug 14, 2016 at 22:29
You mean to only allow, say, 1.22 and not 1.233? Try $validation = ['price' => 'regex:/^[0-9]+(\.[0-9][0-9]?)?$/']; — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Aug 14, 2016 at 22:30

Wiktor Stribiżew · Accepted Answer · 2016-08-14 22:33:26Z

14

You need to use regex delimiters, the most common ones are /.../. Also, to make sure you match the entire string, you need anchors, ^ to anchor at the start and $ to anchor at the end:

$validation = ['price' => 'regex:/^[0-9]+(\.[0-9][0-9]?)?$/'];

answered Aug 14, 2016 at 22:33

Wiktor Stribiżew

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Comments

Maximilian Ast · Accepted Answer · 2019-11-06 12:43:04Z

3

try this code here below

'column' => 'required|regex:/^\d+(\.\d{1,2})?$/',

edited Nov 6, 2019 at 12:43

Maximilian Ast

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answered Nov 6, 2019 at 11:37

Abednego

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Comments

ARIF MAHMUD RANA · Accepted Answer · 2019-05-11 19:45:44Z

1

Just to improve Wiktor answer this part is used [0-9][0-9]? to check if we have one or two digits after decimal points where [0-9]? second one is optional. So this can be simplified by following

'regex:/^[0-9]+(\.[0-9]{1,2})?$/'

Here {1,2} tells how many digits we want after decimal point here at least one. So if someone wants more digits to be fixed e.g any want at most 3 digits after decimal point just change {1,2} to {1,3}.

Also to validate also negative numbers

'regex:/^(-)?[0-9]+(\.[0-9]{1,2})?$/'

Here adding (-)? checks optional minus numbers.

answered May 11, 2019 at 19:45

ARIF MAHMUD RANA

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