PHP unable to parse concatinated string in class

Question

I come across this strange behavior of PHP, assigning string:

class a {
    public $str = "a" . 'b';
}

$obj = new a();
echo $obj->str;

never works, throws following error:

PHP Parse error: syntax error, unexpected '.', expecting ',' or ';' in /var/www/test.php on line 2

while using as plain PHP it works:

$str = "a" . 'b';

What's your question? I believe that's expected behaviour in PHP5 (all?) as you can't have expressions in property defaults? — Jonnix
– Jonnix, Commented Aug 25, 2016 at 13:55
Possible duplicate of Initializing PHP class property declarations with simple expressions yields syntax error — Don't Panic
– Don't Panic, Commented Aug 25, 2016 at 14:12

Awais · Accepted Answer · 2016-08-25 13:56:40Z

2

You cannot perform complex assignment to variable before constructor, you can assign simple string or integer to a variable. dot is consider as function

if you have to assign them you should use constructor.

See http://www.php.net/manual/en/language.oop5.properties.php

answered Aug 25, 2016 at 13:56

Awais

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1 Comment

Riccardo Over a year ago

In this case you don't need a constructor if the PHP version is >=5.6.0, this is the first documentation's example

Nico Savini · Accepted Answer · 2016-08-25 13:56:11Z

0

The dot . operator acts as a function and you cannot declare class variables using function.

If you have an init or construct function you should initialize the variable in such function.

function __construct() {
   $this->str = 'a' . 'b';
}

answered Aug 25, 2016 at 13:56

Nico Savini

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3 Comments

Nico Savini Over a year ago

Then probably you're using php <5.6 Check phpinfo() to see what version of php you're using

Riccardo Over a year ago

In this case you don't need a constructor if the PHP version is >=5.6.0, this is the first documentation's example

Nico Savini Over a year ago

What PHP version are you using? Did you check phpinfo();? What is the output?

Riccardo · Accepted Answer · 2016-08-25 14:17:14Z

0

Look the documentation example.

Check your PHP version.

class a {
    public $str = 'a' . 'b';
}

edited Aug 25, 2016 at 14:17

answered Aug 25, 2016 at 13:58

Riccardo

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