I would like to have this output:
* * *
2 2 2
4 4 4
6 6 6
8 8 8
I cannot get it and I've tried many ways, but my code doesn't seem to work. Here is my current code:
for row in range(3):
print ("*", end = " ")
print ()
for col in range(2,9,2):
print (row, end = " ")
print ()
print()
What do I do?
I don't see why you are using end in your print statements. Keep in mind that you must print line by line. There is no way to print column by column.
print('* * *')
for i in range(2, 9, 2):
print('{0} {0} {0}'.format(i))
For further explanation about the {0}s, look up the format method for strings: https://docs.python.org/2/library/string.html#format-string-syntax
For a start, you only have one row that contains * * * which can be printed at the very top, outside of any loops:
print('* * *')
Next, you would need to start your loop from values 2 (inclusive) and 9 (exclusive) in steps of 2:
for col in range(2,9,2):
You don't need to use any end keyword here, so just printing the row multiple times is sufficient:
print('{0} {0} {0}'.format(i))
So the final block of code looks like:
print('* * *')
for row in range(2,9,2):
print('{0} {0} {0}'.format(row))
You don't need to add another print(), print already ends with a newline anyway.
print('* * *')
for col in range(2,9,2):
print (*[col]*3, sep=' ')
To be more clear.
>>> a = 2
>>> [a]
[2]
>>> [a]*3
[2, 2, 2]
>>> print(*[a]*3, sep=' ') # equal to print(a, a, a, sep=' ')
2 2 2
