Matching string with multilayered array

Question

How can i match variable car with variable array? I need to match every first item (Buick, Mercedes, Chevrolet) with my string. I this case should be logged Buick and Chevrolet:

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];


if (car = array) {
  console.log("Buick and Chevrolet matches.");  
};

But string could be different - sometimes may be matched items 0, sometimes 30 and so on.

georg · Accepted Answer · 2016-10-07 08:38:35Z

1

In modern Javascript you use Set and .filter for this:

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var searchCars = new Set(car.match(/\w+/g));
var found = array.filter(([name]) => searchCars.has(name));

console.log(found);

answered Oct 7, 2016 at 8:38

georg

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1 Comment

Steeve Pitis Over a year ago

Nice one, didn't know Set sound's cool, I will take a look :)

Steeve Pitis · Accepted Answer · 2016-10-07 08:40:29Z

0

You can use Array.reduce here

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];


var matches = array.reduce(function(result, item){
  if(car.indexOf(item[0]) > -1) result.push(item);
  
  return result
}, []);

console.log(matches)

answered Oct 7, 2016 at 8:40

Steeve Pitis

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Comments

Rajesh Dixit · Accepted Answer · 2016-10-07 08:43:08Z

0

You will have to loop over array and you can check for match using string.indexOf()

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];
var matches = [];
var matchesStr = "";
array.forEach(function(item){
  if(car.indexOf(item[0]) > -1){
    matches.push(item[0]);
  }
});

if(matches.length > 0){
  var _last = matches.pop();
  matchesStr = matches.toString() + " and " + _last;
}
else{
  matchesStr = matches.toString()
}
console.log(matchesStr)

Also, if you have option to update your structure, its better to have array of object instead of array of arrays.

answered Oct 7, 2016 at 8:43

Rajesh Dixit

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Comments

Nina Scholz · Accepted Answer · 2016-10-07 08:44:05Z

0

You could split the string and iterate for every element and check against the array.

var car = "Buick, Chevrolet",
    array = [["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"]],
    match = car.split(', ').every(function (a) {
        return array.some(function (b) { return a === b[0]; });
    });

console.log(match);

var car = "Buick, Chevrolet",
    array = [["Buick", "2012", "USA", "1201"], ["Mercedes", "2005", "Germany", "12354"], ["Chevrolet", "1974", "USA", "9401"]],
    match = car.split(', ').every(function (a) {
        return array.some(function (b) { return a === b[0]; });
    });
if (match) {
    console.log(car.split(', ').join(' and ') + ' matches.');
}

edited Oct 7, 2016 at 8:44

answered Oct 7, 2016 at 8:38

Nina Scholz

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Comments

Vladimir M · Accepted Answer · 2016-10-07 08:45:43Z

Using array operations filter and map you can produce the desired filtering. First filter the array to get only elements that match the search criteria. Then I map it to extract only data that is required for further operation.

var string = "Buick, Chevrolet";
var cars = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var findCars= function( arr, str ){
   return arr.filter(
         function(s){
              return str.indexOf(s[0])!==-1;
         }
    ).map(
       function(x){
         return x[0];
       }
    );
}

var res = findCars(cars, string);
console.log( res.join(" and ") + " matches.")

If you need the whole matching data item later, then you should skip the mapping of the result and findCars method will look like this:

var findCars= function( arr, str ){
   return arr.filter(
         function(s){
              return str.indexOf(s[0])!==-1;
         }
    );
}

Nenad Vracar · Accepted Answer · 2016-10-07 08:47:58Z

0

You can use reduce() check for element with indexOf()

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var result = array.reduce(function(r, e, i) {
  if (car.indexOf(e[0]) != -1) {
    r.push(e[0]);
  }
  return r;
}, []).join(' and ') + ' matches.';

console.log(result)

edited Oct 7, 2016 at 8:47

answered Oct 7, 2016 at 8:39

Nenad Vracar

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Comments

Maxx · Accepted Answer · 2016-10-07 08:59:44Z

0

var car = "Buick, Chevrolet";
var array = [
  ["Buick", "2012", "USA", "1201"],
  ["Mercedes", "2005", "Germany", "12354"],
  ["Chevrolet", "1974", "USA", "9401"]
];

var result = car
              .split(', ')
              .reduce(
                (res, car) =>
                  (array.some(([arrayCar]) => car === arrayCar ? res.push(car) : null), res),
                []);

console.log(`${result.join(' and ')} matches`);

answered Oct 7, 2016 at 8:59

Maxx

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