How do you use multiple arguments in {} when using the .format() method in Python

Question

I want a table in python to print like this:

Clearly, I want to use the .format() method, but I have long floats that look like this: 1464.1000000000001 I need the floats to be rounded, so that they look like this: 1464.10 (always two decimal places, even if both are zeros, so I can't use the round() function).

I can round the floats using "{0:.2f}".format("1464.1000000000001"), but then they do not print into nice tables.

I can put them into nice tables by doing "{0:>15}.format("1464.1000000000001"), but then they are not rounded.

Is there a way to do both? Something like "{0:>15,.2f}.format("1464.1000000000001")?

Almost there: "{0:>15.2f}".format(1464.1000000000001) is probably what you want. — user707650
– user707650, Commented Oct 10, 2016 at 20:30
Lots of practical examples at pyformat.info (next to the standard Python documentation). — user707650
– user707650, Commented Oct 10, 2016 at 20:31

Martijn Pieters · Accepted Answer · 2016-10-10 20:34:10Z

9

You were almost there, just remove the comma (and pass in a float number, not a string):

"{0:>15.2f}".format(1464.1000000000001)

See the Format Specification Mini-Language section:

format_spec ::=  [[fill]align][sign][#][0][width][,][.precision][type]
fill        ::=  <any character>
align       ::=  "<" | ">" | "=" | "^"
sign        ::=  "+" | "-" | " "
width       ::=  integer
precision   ::=  integer
type        ::=  "b" | "c" | "d" | "e" | "E" | "f" | "F" | "g" | "G" | "n" | "o" | "s" | "x" | "X" | "%"

Breaking the above format down then:

fill: <empty>
align: <  # left
sign: <not specified>
width: 15
precision: 2
type: `f`

Demo:

>>> "{0:>15.2f}".format(1464.1000000000001)
'        1464.10'

Note that for numbers, the default alignment is to the right, so the > could be omitted.

edited Oct 10, 2016 at 20:34

answered Oct 10, 2016 at 20:30

Martijn Pieters

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1 Comment

Keller Martin Over a year ago

Wow, thanks! I just got around the problem myself by doing two separate iterations of .format(), and it was horrible, this is much more elegant. I couldn't find anything on google about this, so thanks very much!

B. Eckles · Accepted Answer · 2016-10-10 20:31:01Z

3

"{0:15.2f}".format(1464.1000000000001)

I always find this site useful for this stuff:

https://pyformat.info/

answered Oct 10, 2016 at 20:31

B. Eckles

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