Character Pointer to strings

Question

This is C code snippet:

 int main()
 {
   char *names=[ "tom", "jerry", "scooby" ];
   printf("%s", *names[0]);// prints t
   printf("%s", *names[1]);// prints j
  // how to print full word "tom", or full word "jerry"
}

As stated earlier, I want my output to be: tom jerry scooby So using pointers how do I print the whole thing?

Change char *names to char *names[]. Remove * before printf arguments. Look at this: ideone.com/bokCN5 — haccks
– haccks, Commented Oct 14, 2016 at 11:52
change names to be an array of pointer, otherwise it can only hold 1 string. Also the [ should be a {. — mch
– mch, Commented Oct 14, 2016 at 11:53
@ashley It looks like you should re-read the chapter of your C book that explains strings. — Biffen
– Biffen, Commented Oct 14, 2016 at 11:54

unwind · Accepted Answer · 2016-10-14 13:48:09Z

3

Does it compile? Because your array initialization is not correct. To properly declare an array and print them, you can do:

#include <stdio.h>

int main(void)
{
   char *names[]= { "tom", "jerry", "scooby" };
   printf("%s %s %s\n", names[0], names[1], names[2]);
   return 0;
}

edited Oct 14, 2016 at 13:48

unwind

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answered Oct 14, 2016 at 11:56

P.P

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5 Comments

ashley Over a year ago

Oh sorry, i forgot to add the [].

ashley Over a year ago

Can you tell me the output of

ashley Over a year ago

Can you tell me the output of: printf("%s\n",names[0])?

ashley Over a year ago

Thanks, it is tom and jerry. Thank you very much. Have a great day.

P.P Over a year ago

names[0] is the first element in the array names and is a pointer to a string literal. Printing names[0] would print tom.

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