integrate array variables into a command

Question

MY goal is to call the following command:

(echo "test";uuencode testfile1.txt testfile1.txt;uuencode testfile2.txt testfile2.txt)|mail -s "subject" "[email protected]"

calling it in the shell works as expected.

However, I would like to do so, when the uuencode commands are stored in an array:

ARR=("uuencode testfile1.txt testfile1.txt" "uuencode testfile2.txt testfile2.txt")

I've tried the following:

STR=$(IFS=';'; echo "${ARR[*]}");
(echo "test";"$STR")|mail -s "subject" "[email protected]"

but I keep on getting the following error:

uuencode testfile1.txt testfile1.txt;uuencode testfile2.txt testfile2.txt: command not found

How to fix this?

I guess it is not recognizing ; as a command separator

Storing the commands like that is fundamentally wrong. Can you give a more realistic example of multiple commands so that we can suggest a better solution? — chepner
– chepner, Commented Oct 19, 2016 at 15:57

OrangesV · Accepted Answer · 2016-10-19 15:18:28Z

1

Looks like you are storing each command as a string in the array and joining them into a larger string. You can do an eval on the string to execute.

(echo "test";eval "$STR")|mail -s "subject" "[email protected]"

answered Oct 19, 2016 at 15:18

OrangesV

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