Acces a JSON api with python

Question

I am trying to acces data from the pokemon api and get some information from there. First you need to put in a number (only option 1 works right now). Then the pokemon name/number and the url is formed. but I get a lot of errors when

data = json.loads(THEURL)
print(data['forms']['name'])

What am I doing wrong?

#importception
import requests
import json

#import poke api
api_url = 'http://pokeapi.co/api/v2/'

#welke database
def databaseaanvragen():
    print('Welke database wilt u aanvragen?')
    print('Hallo), wat wilt u doen?')
    print('1) Pokemons')
    print('2) Locations')
    print('3) Moves')
    keuze = input('Voer hier het nummer in: ')
    if(keuze.isdigit()):
        keuze = int(keuze)

    if keuze == 1:
        poke_naam = input('Voer de naam of het nummer van de Pokemon in: ')
        poke_value = 'pokemon/' + poke_naam
        return poke_value

#database url en data aanvragen
aangevraagd = api_url + databaseaanvragen()
data = json.loads(aangevraagd)

print(data['forms']['name'])

json.loads expects a string containing the JSON to be decoded, not a URL. json.load instead expects an open file pointer. In short: the json module will not do an actual HTTP request to get the JSON document, that's not its job; you'll need to do that yourself. — deceze
– deceze ♦, Commented Oct 21, 2016 at 13:53

Jack Evans · Accepted Answer · 2016-10-21 13:50:45Z

1

Doesn't actually look like you are querying the JSON api with a GET request at all. You'll need code that looks something like the following:

try:
    r = requests.get(api_url)
except requests.exceptions.RequestException as error:
    print(error)
    sys.exit(1)
else:
   # No Exception was raised :)
   # Decode the JSON from the response content
   json_data = r.json()

answered Oct 21, 2016 at 13:50

Jack Evans

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