How do I assign multiple values to object property with for loop?

Question

I'm trying to assign the name property of obj the [i][0] indices of sampleArr. Console.log(arr[i][0]) outputs "animals", "sopranos", "guitars" with each iteration. However, obj.name = arr[i][0] will only assign obj.name = "guitars".

What explains this behavior, and how could I assign these multiple elements to a single property within a loop?

var sampleArr = [
    ["animals", ["dogs", "cats", "pigs"]],
    ["sopranos", ["Tony", "Carmella", "AJ", "Meadow"]],
    ["guitars", ["Stratocaster", "Telecaster", "Gibson Flying-V"]]
];


function objectifier(arr) {
  var obj = {};
  for (var i = 0; i < arr.length; i++) {
    console.log(arr[i][0])
    obj.name = arr[i][0]
  }
  return obj;
}

So you should use obj.name = [] and then obj.name.push(arr[i][0]) — jonzee
– jonzee, Commented Oct 21, 2016 at 19:30

jonzee · Accepted Answer · 2016-10-21 19:32:16Z

1

how could I assign these multiple elements to a single property within a loop?

To achieve this you have to keep array in this single property, like this:

function objectifier(arr) {
  var obj = {};
  obj.name = [];
  for (var i = 0; i < arr.length; i++) {
    console.log(arr[i][0])
    obj.name.push(arr[i][0]);
  }
  return obj;
}

answered Oct 21, 2016 at 19:32

jonzee

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2 Comments

Zach_is_my_name Over a year ago

End structure should be name: "animals", "sopranos", "guitars"

Zach_is_my_name Over a year ago

This fulfills the quoted criteria but I'm looking for that specific structure

theCJCsoccer · Accepted Answer · 2016-10-21 19:36:22Z

0

Replace

obj.name = arr[i][0]

with

obj[i] = {};
obj[i]["name"] = arr[i][0];

edited Oct 21, 2016 at 19:36

answered Oct 21, 2016 at 19:31

theCJCsoccer

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4 Comments

Zach_is_my_name Over a year ago

"TypeError: Cannot set property 'name' of undefined. Is it not possible to create the name property with bracket notation as obj.name = does...

Zach_is_my_name Over a year ago

Yes. It was replaced verbatim

Zach_is_my_name Over a year ago

Correction. omitted first line.

Zach_is_my_name Over a year ago

It threw only when ob[i] = {} was ommitted, and / or declared outside the loop

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