Running a JS script in a PHP file not working

Question

I am attempting to send a webhook to my discord server when data is inserted into the table, however the function is not being called... Currently it just echos "sendlog()" as shown here: http://prntscr.com/cxqgk5

<!DOCTYPE html>
<html lang="en">
<head>
</head>
	<body>
	<?php
	$token = $_POST["token"];
	$type = $_POST["type"];
	$pid = $_POST["pid"];
	$sid = $_POST["sid"];
	$gid = $_POST["gid"];
	$name = $_POST["name"];
	$players = $_POST["players"];
	$max = $_POST["max"];
	$cdesc = $_POST["cdesc"];
	$sus = $_POST["sus"];

	if($token == 'DS_443'){
		$con =  mysqli_connect("localhost","**","**","**");

		if(mysqli_connect_errno()){
			echo(mysqli_connect_error());
		}
	
		if($type == 'edit' and $players !=NULL and $sid !=NULL){
			$con->query("UPDATE OnlineServers SET ServerCurrent='$players' WHERE ServerID='$sid'");
		} elseif($type == 'remove' and $sid !=NULL){
			$con->query("DELETE FROM OnlineServers WHERE ServerID='$sid'");
		} elseif($type == 'add' and $sid !=NULL and $gid !=NULL and $name!=NULL and $players !=NULL){
			$con->query("INSERT INTO OnlineServers (GameId,GameName,GameMax,ServerCurrent,ServerID,Command) VALUES ('$gid','$name','$max','$players','$sid','TEST')");
	?>
			sendLog();
	<?php
		} elseif($type == 'call'){
			$con->query("INSERT INTO Calls     (Caller,CallerID,CallID,CallDesc,Suspect,SuspectID,ServerID,GameID) VALUES                  ('$pid','$name','$cdesc','$sus')");
		}        
	} else {
	?>
		sendLog();
	<?php
	}
?>

<script>
	function sendLog(){ 
		var hookurl =  "webhookurl"
		let tosend = {
		'Server added;',
		'Game Name: ',
		'Game ID: ',
		'Server ID: ',
		},
		var msgJson = {
			"attachments": [
				{
				"color": "#CC09EF",
				"text": tosend,
				"footer": "Infius Game Logs",
				"footer_icon": "http://deersystems.net/assets/images/nfius.png",
				}
			]
		}
		post(hookurl, msgJson); 
	}
</script>

<script>
	function post(url, jsonmsg){
		xhr = new XMLHttpRequest();
		xhr.open("POST", url, true);
		xhr.setRequestHeader("Content-type", "application/json");
		var data = JSON.stringify(jsonmsg);
		xhr.send(data);
		xhr.onreadystatechange = function() {
			if(this.status != 200){
				alert("ttt");
			}
		}
	}
</script>
</body>

user2315596 · Accepted Answer · 2016-10-23 02:14:34Z

2

java script function should be wrapped inside script tags

<script type="text/javascript">
    sendLog();
    </script>

OR

<?php

echo '<script type="text/javascript">',
     'sendLog();',
     '</script>'
;

?>

answered Oct 23, 2016 at 2:14

user2315596

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Comments

Ashokkumar M. Prajapati · Accepted Answer · 2016-10-23 02:04:36Z

0

You have output sendLog(); whithout script tag so, it will be consider normal text. If you want to call that function then you need it between script tag.

Also, you should have clean formatting of code. And avoid multiple script tag on same pages. add all js code in single script tag.

answered Oct 23, 2016 at 2:04

Ashokkumar M. Prajapati

4934 silver badges12 bronze badges

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