I have a list which I want to convert into matrix. But when using numpy I am not able to remove inverted commas.
List -
[['b', 'd', 'a', 'c'], ['b1', 'd1', 'a1', 'c1'], ['b2', 'd2', 'a2', 'c2']]
Using Numpy -
[['b' 'd' 'a' 'c']
['b1' 'd1' 'a1' 'c1']
['b2' 'd2' 'a2' 'c2']]
What I need -
b d a c
b1 d1 a1 c1
b2 d2 a2 c2
Thanks
No need to numpy you can make it pure python.
a = [['b', 'd', 'a', 'c'], ['b1', 'd1', 'a1', 'c1'], ['b2', 'd2', 'a2', 'c2']]
for b in a:
print ' '.join(b)
Quotes with the text means that you have the object of str type. You need not worry about them because when you do print, these will be removed. For example:
>>> my_list = [['b', 'd', 'a', 'c'], ['b1', 'd1', 'a1', 'c1'], ['b2', 'd2', 'a2', 'c2']]
>>> my_list[0][0] # without print, shows content with quotes
'b'
>>> print my_list[0][0] # with print, content without quotes
b
>>>
In order to print the content in the format you mentioned, you may do:
>>> for sub_list in my_list:
... print ' '.join(sub_list) # join to make single of object in sub_list
...
b d a c
b1 d1 a1 c1
b2 d2 a2 c2
where my_list is the list mentioned in the question.
If all you want is to print it such that cells are space separated and rows are line-break separated :
print ('\n'.join([' '.join(i) for i in lst]))
numpywith the matrix of strings?