org.json.JSONObject$1 cannot be converted to JSONObject error while parsing json string

Question

For parsing json i use JSONArray and JsonObject:

 protected void parseJson()
    {
        JSONObject object=null;
        try {

            object=new JSONObject(json);
            myArray=object.getJSONArray(MY_ARRAY);
            Log.e("Array Length",""+myArray.length());
            key_id=new String[myArray.length()];
            key_name=new String[myArray.length()];

            for (int i=0;i<=myArray.length();i++)
            {
                JSONObject fetchObject=myArray.getJSONObject(i);

                    key_id[i] = fetchObject.getString(KEY_ID);
                    key_name[i] = fetchObject.getString(KEY_NAME);


            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

JSON DATA:

 {
        "data": [{
            "key": 1,
            "myval": "hello"
        }, {
            "key": 1,
            "myval": "hello"
        }, {
            "key": 1,
            "myval": "hello"
        }, null, {
            "key": 1,
            "myval": "hello"
        }, {
            "key": 1,
            "myval": "hello"
        }]
    }

My problem is that when fetchObject get the null object it give me org.json.JSONObject$1 cannot be converted to JSONObject in try catch . Please help me how can i solve this.....Thanks for reading....

Why are you working so hard on parsing code instead of using a json parsing library like GSON is Jackson ? — Shai Levy
– Shai Levy, Commented Nov 16, 2016 at 12:39
your json structure is saying something else and your code is doing something else , it's looks suspicious — Pavneet_Singh
– Pavneet_Singh, Commented Nov 16, 2016 at 12:45
Why the api guy send you a null??? you can ask if key and myval is blank, they can give blank string like { "key": 1, "myval": "" } Then your problem will be solved — AmeeJoshi
– AmeeJoshi, Commented Nov 16, 2016 at 12:50

nzala · Accepted Answer · 2016-11-18 07:37:50Z

3

if(obj.length() == 0)

is what I would do.

JSONObject fetchObject;

if(flowerArray.getJSONObject(i).length() !=0)

/

fetchObject = flowerArray.getJSONObject(i)
    if(fetchObject== null)

edited Nov 18, 2016 at 7:37

answered Nov 16, 2016 at 13:12

nzala

3724 silver badges10 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Manish · Accepted Answer · 2016-11-17 12:40:07Z

0

After reading JsonArray and JsonObject doc i understand how to sort out this problem.

protected void parseJson()
    {
        JSONObject object=null;
        try {

            object=new JSONObject(json);
            myArray=object.getJSONArray(MY_ARRAY);
            Log.e("Array Length",""+myArray.length());
            key_id=new String[myArray.length()];
            key_name=new String[myArray.length()];

            for (int i=0;i<=myArray.length();i++)
            {

                JSONObject fetchObject=myArray.optJSONObject(i);

                    if(fetchObject==null)
                   {
                     //do nothing
                   }
                   else
                   {
                    key_id[i] = fetchObject.getString(KEY_ID);
                    key_name[i] = fetchObject.getString(KEY_NAME);

                   }
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

answered Nov 17, 2016 at 12:40

Manish

3342 silver badges13 bronze badges

1 Comment

DominikAngerer Over a year ago

actually it's exactly what nzala told you to try :) :+1: for you nzala

Collectives™ on Stack Overflow

org.json.JSONObject$1 cannot be converted to JSONObject error while parsing json string

2 Answers 2

Comments

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related