PHP doesn't recognize input field's name

Question

I have an input field with name:"fsearch" from which i want to get inputted data. I am using if(issetwith $_POST properties but php cannot detect it,it is returning false.Here is my code

<!----------------------------------------------------------------
                              HTML
----------------------------------------------------------------->
<form method="POST">
<p>Търсене на храни: <input type="text" name="fsearch" id="food_search"></p>
</form>
<!----------------------------------------------------------------
                             PHP
----------------------------------------------------------------->
<?php
if(isset($_POST['fsearch']) && !empty($_POST['fsearch'])) {
echo "True!";
}
else{
echo "false";
}
?>

I don't know where i have a mistake :/

EDIT:I am using it for google like instant search,i don't really need submit button.It must compare inputted information with database ROW and if there are letters matched,to print it out.

Sorry i don't know what you mean.I need Sumbit button? I am pretty new and still stupid,so if you can please explain. <3 — Tsvetomirov Yordan
– Tsvetomirov Yordan, Commented Jan 15, 2017 at 19:25
yes add a submit button into the form also in the declaration you should really use action="somepage.php" even when you are submitting to the same page. — CodingInTheUK
– CodingInTheUK, Commented Jan 15, 2017 at 19:27

N. Thanasis · Accepted Answer · 2017-01-15 19:37:25Z

1

You need to correct your form, here is how.

    <form method="POST" action='myphpfile.php'>
    <p>Търсене на храни: <input type="text" name="fsearch" id="food_search">      </p>
    <input type="submit" value="Submit">
    </form>

answered Jan 15, 2017 at 19:37

N. Thanasis

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3 Comments

Tsvetomirov Yordan Over a year ago

I copied your example and pasted my page in it,but it is still returning false..(also deleted cache)

N. Thanasis Over a year ago

I just tested it and it works fine. Please make sure to change the value 'myphpfile.php', to the actual name of the file you are using to post your form. If you are posting to the same file that your form is, use action="<?php echo $PHP_SELF;?>

Tsvetomirov Yordan Over a year ago

Well the bad is mine i wasn't really specific what i want .The code works,but i cannot really explain what i want,thats why i will mark it as an answer,it might help somebody.And when i feel ready with my question will ask again,and be more specific.Thanks for answer mate <3

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