PHP exec() and shell_exec() not outputting everything

Question

I am trying to get a certain detail from an external program using shell_exec() in PHP. Here is what I am querying:

$output = shell_exec('vanitygen.exe 1z');

When doing this in the command prompt on windows it returns this information:

Difficulty: 1353
Pattern: 1z
Address: address
Privkey: private_key

However, when running the same command using PHP shell_exec (and exec) only this is returned:

Pattern: 1z
Address: address
Privkey: private_key

Is there any way to have PHP give all information, including the 'Difficulty: 1353' line?
Thanks.

I'll bet that the missing output is in STDERR.

Sammitch
– Sammitch

2017-02-11 02:11:50 +00:00
Commented Feb 11, 2017 at 2:11 — Sammitch
– Sammitch, Commented Feb 11, 2017 at 2:11
You were right.

Minifrij
– Minifrij

2017-02-11 02:15:54 +00:00
Commented Feb 11, 2017 at 2:15 — Minifrij
– Minifrij, Commented Feb 11, 2017 at 2:15

Minifrij · Accepted Answer · 2017-02-11 02:17:51Z

1

Turns out that the information that I wanted was stored in STDERR.
To get this information, you simply have to append this to the end of the exec query:

2>&1

In this case, this turns the query from:

$output = shell_exec('vanitygen.exe 1z');

to

$output = shell_exec('vanitygen.exe 1z 2>&1');

answered Feb 11, 2017 at 2:17

Minifrij

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1 Comment

Sammitch Over a year ago

Though it's likely overkill, you can also use proc_open() which allows you to manage all I/O streams for the process.

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