This code below is to make a list of the bigger number of the two lists in the same index positions. How can I rewrite this code with a while loop instead of a for loop?
a = [7,12,9,14,15,18,12]
b = [9,14,8,3,15,17,15]
big = []
for i in range(len(a)):
big.append(max(a[i],b[i]))
print(big)
[9, 14, 9, 14, 15, 18, 15]
You can use pop() in order to poop the first item of both lists each time till a or b evaluates as True (it's contain items):
In [15]: while a:
big.append(max(a.pop(0),b.pop(0)))
....:
In [16]: big
Out[16]: [9, 14, 9, 14, 15, 18, 15]
One way is this with while
a = [7, 12, 9, 14, 15, 18, 12]
b = [9, 14, 8, 3, 15, 17, 15]
big = []
i = 0
while i < len(a):
big.append(max(a[i], b[i]))
i += 1
print big
Using zip and list comprehension:
a = [7, 12, 9, 14, 15, 18, 12]
b = [9, 14, 8, 3, 15, 17, 15]
big = [max(t) for t in zip(a, b)]
Using while:
a = [7, 12, 9, 14, 15, 18, 12]
b = [9, 14, 8, 3, 15, 17, 15]
big = []
i = 0
while i < len(a):
big.append(max(a[i], b[i]))
i += 1
You can try this :
a = [7,12,9,14,15,18,12]
b = [9,14,8,3,15,17,15]
big = []
i=0
while i<len(a):
if a[i]<b[i]:
big.append(b[i])
i+=1
else:
big.append(a[i])
i+=1
print(big)
You can also try with zip() and list comprehension like so:
a = [7,12,9,14,15,18,12]
b = [9,14,8,3,15,17,15]
big = [max(c) for c in zip(a,b)]
print big
Output:
[9, 14, 9, 14, 15, 18, 15]
