Checking if a string isn't a space in Javascript

Question

So I have a program that counts the words in a document that is loaded into an iFrame, all of the newline characters are replaced by a space, then the string is split by spaces, I then want to add them to a map as the key and set their value to 1 if they're not in the map or not a space, this is where I'm having the problem because it's still counting each space in the string , I feel like I'm being really stupid and missing something obvious...

var innerDoc = document.getElementById("pageinframe");
var innerDocContent = innerDoc.contentDocument.body.innerHTML;
var split = strip(innerDocContent).replace(/(\r\n|\n|\r)/gm, " ").split(" ");
var obj = new Map();
for (var x = 0; x < split.length; x++) {
     console.dir(typeof split[x]);
     if(!obj.has(split[x]) && (split[x] != " ")) {
         obj.set(split[x], 1);
      }
      else if (split[x] != " ") {
         obj.set(split[x], obj.get(split[x])+1);
      }
}

function strip(str) {
    var tmp = document.createElement("DIV");
    tmp.innerHTML = str;
    return tmp.textContent || tmp.innerText || "";
}

If you use 'split' doesn't it already give you an array of the words, without the space characters ? — Romi Halasz
– Romi Halasz, Commented Feb 15, 2017 at 8:55

Álvaro Touzón · Accepted Answer · 2017-02-15 08:59:32Z

1

There are something, icant understand. When you split(' '). the array not contains ' ', only words!!!, https://www.w3schools.com/jsref/jsref_split.asp. Son Why need to testif is white space. Then i think, it could be in:

.replace(/(\r\n|\n|\r)/gm, " ")

answered Feb 15, 2017 at 8:59

Álvaro Touzón

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Comments

Chaz · Accepted Answer · 2017-02-15 09:06:18Z

0

The split array contained "" not " " like I originally thought. Like I said I was missing something really obvious, just needed to see what was in the array.

answered Feb 15, 2017 at 9:06

Chaz

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Ravindra Singh · Accepted Answer · 2017-02-15 09:06:53Z

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var innerDoc = document.getElementById("pageinframe");

var innerDocContent = innerDoc.contentDocument.body.innerHTML;

var split = strip(innerDocContent).replace(/(\r\n|\n|\r)/gm, " ").split(" ");
var obj = new Map();
for (var x = 0; x < split.length; x++) {

     // Removing NaN for string
     if(split[x].charCodeAt(0))
     {
         if(!obj.has(split[x]) && (split[x] != " ")) {
             obj.set(split[x], 1);
          }
          else if (split[x] != " ") {
             obj.set(split[x], obj.get(split[x])+1);
          }
    }
}

function strip(str) {
    var tmp = document.createElement("DIV");
    tmp.innerHTML = str;
    return tmp.textContent || tmp.innerText || "";
}

console.log(obj);

answered Feb 15, 2017 at 9:06

Ravindra Singh

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1 Comment

Ravindra Singh Over a year ago

I hope this will help you :)

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