I try to loop through folder and read files but only the first file will open and read correctly but the second files print the name and through an error "IOError: [Errno 2] No such file or directory:". I have tried the following
for filename in os.listdir("pathtodir\DataFiles"):
if filename.endswith(".log"):
print(os.path.join("./DataFiles", filename))
with open(filename) as openfile:
for line in openfile:
........
os.listdir() gives you only the filename, but not the path to the file:
import os
for filename in os.listdir('path/to/dir'):
if filename.endswith('.log'):
with open(os.path.join('path/to/dir', filename)) as f:
content = f.read()
Alternatively, you could use the glob module. The glob.glob() function allows you to filter files using a pattern:
import os
import glob
for filepath in glob.glob(os.path.join('path/to/dir', '*.log')):
with open(filepath) as f:
content = f.read()
Using os.listdir(...) only returns the filenames of the directory you passed, but not the full path to the files. You need to include the relative directory path as well when opening the file.
basepath = "pathtodir/DataFiles/"
for filename in os.listdir(basepath):
if filename.endswith(".log"):
print(os.path.join("./DataFiles", filename))
with open(basepath + filename) as openfile:
for line in openfile:
........
./DataFiles, according to the line of code that retrieves the list frompathtodir\DataFiles. You should first figure out where you're looking for the files at, settle on a forward or backslash (but not both), and then be consistent when you use that pathname. You have to open the file in the same folder you got it's name from; your code does not do that, because it tries to openfilenamewithout a path. The code you're using tries to access the same file in three separate locations, and it's only in one of them.