Push array from function which places into another function

Question

I have a questions about nested functions

How can I get b array which contains [1, 2, 3] here:

function someFunc() {
  const a = [{
    id: 1
  }, {
    id: 2
  }, {
    id: 3
  }]
  const b = []
  
  function someOtherFunc() {
    a.forEach(i => {
      b.push(i.id)
    })
  }
  return b
}

console.log(someFunc())

you aren't calling someOtherFunc anywhere...

Neutrosider
– Neutrosider

2017-03-13 22:17:05 +00:00
Commented Mar 13, 2017 at 22:17 — Neutrosider
– Neutrosider, Commented Mar 13, 2017 at 22:17

kind user · Accepted Answer · 2017-03-13 23:04:07Z

3

You are getting an empty array, because the someOtherFunc function wasn't executed.

function someFunc() {
  const a = [{ id: 1}, { id: 2 }, { id: 3 }];
  let b = [];
  
  someOtherFunc();
  
  function someOtherFunc() {
    a.forEach(i => {
      b.push(i.id)
    })
  }
  return b
}

console.log(someFunc())

Or quicker solution, using Array#map.

function someFunc() {
  console.log([{ id: 1 }, { id: 2 }, { id: 3 }].map(v => v.id));
}

someFunc();

edited Mar 13, 2017 at 23:04

answered Mar 13, 2017 at 22:17

kind user

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2 Comments

mhodges Over a year ago

Might be worth mentioning that return a.map(...) would be much more efficient here.

mhodges Over a year ago

No.. I meant completely remove someOtherFunc() and b altogether... This function can be 2 lines long

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