PhpStorm undefined object if class is included in conditional statement

Question

JetBrains PhpStorm doesn't detect a variable as an object of a class if it's included in a conditional statement. For example, here are my files:

config.php:

if( in_array('DATABASE', $include) ){
        require_once( 'database/Database.class.php' );
        $db = new Database();
}

index.php

$include = ['DATABASE'];
require_once('config.php');
$db...  //<< Here $db is undefined

if I include database class in config.php file without checking the condition, it'll be OK and I can use $db as an instance of Database class.

I also tried to uncheck Ignore 'include' and 'require' statements. in the inspector but it just ignores undefined variables, $db is not detected as object by the way so I can't see it's methods and properties.

How should I fix this issue?

Andy Hoffner · Accepted Answer · 2017-03-16 15:21:29Z

2

It's not sure what $db is precisely because it was defined inside the if statement. It won't know until run time if DATABASE is in the $include array, so $db may or may not be defined at all.

You can work around it by using PHPDoc comments to hint at the type instead. At the top of index.php add something like:

<?
/**
 * @var Database $dba
 */

answered Mar 16, 2017 at 15:21

Andy Hoffner

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3 Comments

asDca21 Over a year ago

It's awesome and works perfectly but is there any way to implement the hint in config.php so I won't need to type it in all the files? (specially because other objects have this problem, just like $db).

Andy Hoffner Over a year ago

@var level comments I believe only apply to the page scope. Another workaround would be to wrap config.php code in a class, and specify $db as a property of that class, using a similar typehint in the PHPDoc comment for that property. It'll use that type hint on other pages. lmk if that's confusing and I'll edit my question with an example.

LazyOne Over a year ago

@asDca21 Try with @global instead of @var and do that in that config.php file -- in theory should work.

Tony T. · Accepted Answer · 2017-03-16 15:50:12Z

0

Are you sure that you include config.php after you declare $include = ['DATABASE']; ? Seems like you don't.

answered Mar 16, 2017 at 15:50

Tony T.

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1 Comment

asDca21 Over a year ago

Yes. I edited the question and added the line I had forgotten.

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