Regex expression

Question

I would like to obtain the two numbers on this expression:

s= "sfsdfafafadfafafa **34/23**"

I tried this:

import re 
re.search("\\*\\*[0-9][0-9]\\/[0-9][0-9]\\*\\*",s)

But Im getting None as an ouput, when at least I was expecting to get the expression.

Edit: Please take into consideration the ** as I would like to take them into account

Edit: The numbers can be between 1 and 6 digits

Use regex = r"\*\*(\d+)\/(\d+)\*\*" and extract first and second captured group to get the two digits. — Tushar
– Tushar, Commented Apr 6, 2017 at 3:51
Your example regular expression should match fine, but you haven’t showed the code you actually used (re.search takes two arguments, so it can’t return None here). — Ry-
– Ry- ♦, Commented Apr 6, 2017 at 3:51

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

Use this regex instead:

(\*\*\d+\/\d+\*\*)

\d is the same as [0-9], it denotes all digits.

Regex101:

Apply to your code (You omitted the second argument):

import re 
re.search("(\*\*\d+\/\d+\*\*)", inputString)

CommunityBot

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answered Apr 6, 2017 at 3:50

Neil

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Thanks, and that regex link is very useful

m_callens · Accepted Answer · 2017-04-06 03:53:01Z

0

Doing:

re.findall(r'\*\*(\d{2})\/(\d{2})\*\*', 'sfsdfafafadfafafa **34/23**')

will return an array containing a tuple [('34', '23')] that you can use to get the values from the string.

answered Apr 6, 2017 at 3:53

m_callens

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