Converting an int to a float in C

Question

I'm having trouble converting an int into a float. I tried to type convert but it doesn't seem to work. What am I doing wrong?

float *six(const int *x) {
    float *p = malloc(sizeof(x));
    p = (float *)x;
    return p;
}

int main() {
    float *p_six;
    int i4 = 4, i432 = 432;

    p_six = six(&i4);
    printf("%d == %f\n", i4, *p_six);
    free(p_six);
}

The p = (float *)x; assignment in the function obliterates the pointer to the memory allocated in the previous line, so you have a memory leak every time you call the function. — Jonathan Leffler
– Jonathan Leffler, Commented Apr 8, 2017 at 20:52

dbush · Accepted Answer · 2017-04-08 20:24:56Z

3

You can't point a float * to an int and expect it to be interpreted properly. They have very different representations, so you'll end up with garbage.

All you need to do is assign your int value to a float and it will be converted.

int main()
{
    float f;
    int i = 4;

    f = i;
    printf("%d == %f\n", i, f);
    return 0;
}

Output:

4 == 4.000000

answered Apr 8, 2017 at 20:24

dbush

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