Converting a Batch script to Shell

Question

I'm trying to convert a Batch script to a shell. The script collect the name of the file that start with a certain String, and simply log it.

here is my batch Script :

PATH = E:/DATA
str_Begin_With = Employee
set FILE_NAME= for %%x in (%PATH%/%str_Begin_With%*.txt) do set FILE_NAME=%%~x
ECHO %FILE_NAME%

This is my Shell attempt:

export FILE_NAME=
for x in [$PATH/$str_Begin_With*.txt]; 
do FILE_NAME= x

Can someone explain to me how does it work on shell, i'm not familiar with it

Since the batch isn't valid it is difficult to guess what you have in mind. — user6811411
– user6811411, Commented May 9, 2017 at 22:25
the batch is valid, i've tried it, i just don't know how to convert it to shell — Anna
– Anna, Commented May 10, 2017 at 8:24

Steeve · Accepted Answer · 2017-05-10 12:32:46Z

1

Try Using Basename.

In your Case:

for file in "$PATH"/$str_Begin_With*.txt
do
NAME=$(basename "$file")
echo "$NAME"
done

answered May 10, 2017 at 12:32

Steeve

2761 gold badge2 silver badges10 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

that's what i was looking for ! Thank's