I'm trying to do regex pattern which will match to this:
Name[0]/Something
or
Name/Something
Verbs Name and Something will be always known.
I did for Name[0]/Something, but I want make pattern for this verb in one regex
I've tried to sign [0] as optional but it didn't work :
var regexPattern = "Name" + @"\([\d*\]?)/" + "Something"
Do you know some generator where I will input some verbs and it will make pattern for me?
Use this:
Name(\[\d+\])?\/Something
\d+ allows one or more digits\[\d+\] allows one or more digits inside [ and ]. So it will allow [0], [12] etc but reject [](\[\d+\])? allows digit with brackets to be present either zero times or once\/ indicates a slash (only one)Name and Something are string literalsYou were close, the regex Name(\[\d+\])?\/Something will do.
Name[0/Something as wellThe problem is with first '\' in your pattern before '('.
Here is what you need:
var str = "Name[0]/Something or Name/Something";
Regex rg = new Regex(@"Name(\[\d+\])?/Something");
var matches = rg.Matches(str);
foreach(Match a in matches)
{
Console.WriteLine(a.Value);
}
var string = 'Name[0]/Something';
var regex = /^(Name)(\[\d*\])?\/Something$/;
console.log(regex.test(string));
string = 'Name/Something';
console.log(regex.test(string));You've tried wrong with this pattern: \([\d*\]?)/
No need to use \ before ( (in this case)
? after ] mean: character ] zero or one time
So, if you want the pattern [...] displays zero or one time, you can try: (\[\d*\])?
Hope this helps!
i think this is what you are looking for:
Name(\[\d+\])?\/Something
Name litteral
([\d+])? a number (1 or more digits) between brackets optional 1 or 0 times
/Something Something litteral
+ right after the d, signifying 1 or more of this character (number)