remove numbers from an Array of Strings

Question

public class ChessMethod {
  public static void main(String[] args) {

      String line=" 1.d4 Nf6 2.c4 g6  0-1]";
      String[] elements = line.split("[\\s.]+");
      String first = elements[1];
      String[] trailing = Arrays.copyOfRange(elements,1,elements.length);

      System.out.println(Arrays.deepToString(trailing));

  }
}

Output= [1, d4, Nf6, 2, c4, g6, 0-1]]

I would like to get rid of the "1.","2." part of the move list and only keep the

d4, Nf6... I was going to add them to a list.

Is there a better way to do this with a delimiter? Do I have to make a method that checks the (if there is one) numerical value of every String in my Array, and saves the ones that dont have one?

Use "\\s*\\d+\\.\\s*" as delimiter, then split on whitespace? — user3458
– user3458, Commented May 21, 2017 at 23:15

A Paul · Accepted Answer · 2017-05-21 23:15:50Z

2

String line=" 1.d4 Nf6 2.c4 g6  0-1]";
        String[] elements = line.split("[\\s.]+");
        List<String> sts  = new ArrayList<>();
        for(String st : elements) {
            if(st.matches(".*[a-z].*"))
                sts.add(st);
        }
        System.out.println(sts);

This ouputs

[d4, Nf6, c4, g6]

May be this is what you want, if I am not missing anything

answered May 21, 2017 at 23:15

A Paul

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3 Comments

Charlie CatLitter Over a year ago

This is what I was looking for! at the if statement, is that regex or a delimiter? What is the difference between them. Thanks!

A Paul Over a year ago

st.matches(".*[a-z].*") checks if the string contains any char between a-z. If you want the add capital char also .. you can just change it to [a-zA-Z]

A Paul Over a year ago

thats regex.... that just searching for any char between a-z like I mentioned in prev comment. Let me know if you have any other question. Mark the answer correct please if this helped. Thank you !

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