Using Array.prototype.concat(), when I write this code:
var g = [1, 11, 111];
var ga = [12, 122, 1222];
var gb = [13, 133, 1333];
var gc = g.concat(ga, [123, gb]);
console.log(gc);It gives me the following result: [1, 11, 111, 12, 122, 1222, 123, Array(3)]
Why is Array(3) added to the resulting array?
[123,gb] does not concat arrays it's an array inside of an array, what you want is this:
var g = [1,11,111];
var ga = [12,122,1222];
var gb = [13,133,1333];
var gc = g.concat(ga,[123].concat(gb));
//or better
var gc2 = g.concat(ga, 123, gb);
console.log(gc, gc2);
Use ES6 style syntax spread
var g = [1,11,111];
var ga = [12,122,1222];
var gb = [13,133,1333];
var gc = [...g,...ga,123,...gb];
console.log(gc);One of the values in the array is an array with three items in it and you are looking at it using a tool that gives you a summary of the data rather than a fully expanded view of it.
This will help you!!
var g = [1,11,111];
var ga = [12,122,1222];
var gb = [13,133,1333];
var gc = g.concat(ga,123,gb);
console.log(gc);