The following python code gives me the different combinations from the given values.
import itertools
iterables = [ [1,2,3,4], [88,99], ['a','b'] ]
for t in itertools.product(*iterables):
print t
Output:-
(1, 88, 'a')
(1, 88, 'b')
(1, 99, 'a')
(1, 99, 'b')
(2, 88, 'a')
and so on.
Can some one please tell me how to modify this code so the output looks like a list;
188a
188b
199a
199b
288a
You'll have to convert the numbers to strings, then join the results:
print ''.join(map(str, t))
You could avoid having to convert if you made your inputs strings to begin with:
iterables = [['1', '2', '3', '4'], ['88', '99'], ['a', 'b']]
for t in itertools.product(*iterables):
print ''.join(t)
If all you want is to print the values together (and not do anything with them otherwise) then use print() as a function (by using the from __future__ import print_function Python 2 feature switch or by using Python 3):
from __future__ import print_function
iterables = [[1, 2, 3, 4], [88, 99], ['a', 'b']]
for t in itertools.product(*iterables):
print(*t)
You can try this:
iterables = [ [1,2,3,4], [88,99], ['a','b'] ]
new_list = [''.join(map(str, i)) for i in itertools.product(*iterables)]
list in the map? Just do map(str, i)
str.join() works faster with list inputs).