Suppose there are two run function in app:
angular.module('exmple',[])
.run(function(){
console.log('second');
})
.run(function(){
console.log('first');
});Is there any way to execute runs based on priority?
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what priority ?dfsq– dfsq2017-06-04 22:38:18 +00:00Commented Jun 4, 2017 at 22:38
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A run block executed first if its priority is the biggest.Mostafa Barmshory– Mostafa Barmshory2017-06-04 22:40:54 +00:00Commented Jun 4, 2017 at 22:40
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but what do you mean with priority of a run block? you can define priority on components/directives, but a run is executed simply when is found. Why you don't just structure your code in order to execute the one you want before the other one?quirimmo– quirimmo2017-06-04 22:43:27 +00:00Commented Jun 4, 2017 at 22:43
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One of the run block are responsible to load configuration from server and init some basic services. Others are from modules and plugins. The first must be executed before the others.Mostafa Barmshory– Mostafa Barmshory2017-06-05 06:22:19 +00:00Commented Jun 5, 2017 at 6:22
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1 Answer
If code is in a service, it will run in order of dependency:
angular.module('exmple',[])
.run(function(firstService){
console.log('second');
})
.service("firstService", function(){
console.log('first');
});
By having the run block define firstService as a dependency, the dependency injector will initialize that service before running the code of the run block.
The Demo
angular.module('app',[])
.run(function(firstService){
console.log('second');
})
.service("firstService", function(){
console.log('first');
});<script src="//unpkg.com/angular/angular.js"></script>
<div ng-app="app">
</div>
