How to sort an array chronologically?

Question

I shall like to sort out an array in order chronological. I know not at all how to take myself there ... Here is the array:

 [["FM", "TEL", "ID", "2017-06-17 18:16:29 +0000", "TYPE", "inbox"], ["FM", "TEL", "ID", "2017-06-17 18:17:24 +0000", "TYPE", "no", "send"], ["Jm", "TEL", "ID", "2017-06-17 19:25:27 +0000", "TYPE", "no", "send"]]

I tried with that but that did not work ....

 str.sort({$0[3].date > $1[3].date})

I shall like the most recent date at the beginning, the output should be like this:

 [["Jm", "TEL", "ID", "2017-06-17 19:25:27 +0000", "TYPE", "no", "send"], ["FM", "TEL", "ID", "2017-06-17 18:17:24 +0000", "TYPE", "no", "send"], ["FM", "TEL", "ID", "2017-06-17 18:16:29 +0000", "TYPE", "inbox"], ["FM", "TEL", "ID", "2017-06-17 18:17:24 +0000", "TYPE", "no", "send"]]

This has the thing you need in every language - rosettacode.org/wiki/Sort_using_a_custom_comparator — Udayraj Deshmukh
– Udayraj Deshmukh, Commented Jun 18, 2017 at 7:28
Did you try str.sort {$0[3].date > $1[3].date} stackoverflow.com/questions/26719744/… — Udayraj Deshmukh
– Udayraj Deshmukh, Commented Jun 18, 2017 at 7:29
$0[3].date What's that call .date ? $0[3] is a String. You need to convert it into (NS)Date with (NS)DateFormatter. Also, I strongly suggest to use a proper class/struct rather than a array to keep your data. — Larme
– Larme, Commented Jun 18, 2017 at 10:28

Kristijan Delivuk · Accepted Answer · 2017-06-18 07:48:00Z

1

Use dateformatter to convert strings into date first and then compare them:

let str = [["FM", "TEL", "ID", "2017-06-17 18:16:29 +0000", "TYPE", "inbox"], ["FM", "TEL", "ID", "2017-06-17 18:17:24 +0000", "TYPE", "no", "send"], ["Jm", "TEL", "ID", "2017-06-17 19:25:27 +0000", "TYPE", "no", "send"]]

let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd HH:mm:ss Z"

let sorted = str.sorted(by: {dateFormatter.date(from: $0[3])!  > dateFormatter.date(from: $1[3])!})

answered Jun 18, 2017 at 7:48

Kristijan Delivuk

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