replace substrings in list

Question

I am looking forward to get rid of a space that is after each element in my list:

  list1 = ['Aena', 'Cellnex Telecom', 'Amadeus', 'Abertis']

in order to obtain the list like this:

  list1 = ['Aena','Cellnex Telecom','Amadeus','Abertis']

I have tried the following loop but returns the same initial list:

new_list = [stocks.replace(" ","") for stocks in list1]

and

new_list = [stocks.replace(", '",",'") for stocks in list1]

print(new_list)

Could anyone help me to obtain the desired list without the spaces?

I think you have to understand, that print(..) prints the representation of a list. With the list comprehension, you alter the elements themselves. Afaik you can't do much about how print prints the list itself. But you can write your own print method. — willeM_ Van Onsem
– willeM_ Van Onsem, Commented Jun 25, 2017 at 14:57

willeM_ Van Onsem · Accepted Answer · 2017-06-25 14:59:39Z

5

I think you have to understand, that print(..) prints the representation of a list (which is a comma separated list surrounded by square brackets).

With the list comprehension, you alter the elements themselves. As far as I know you can't do much about how print prints the list itself. But you can write your own print method.

We can do this by using a join on the repr(..) of the elements, and surround it by square brackets, like:

print('[{}]'.format(','.join(repr(x) for x in list1)))

This prints:

>>> print('[{}]'.format(','.join(repr(x) for x in list1)))
['Aena','Cellnex Telecom','Amadeus','Abertis']

answered Jun 25, 2017 at 14:59

willeM_ Van Onsem

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3 Comments

Uriel Over a year ago

completely identical expressions. what are the odds 😂😂?

willeM_ Van Onsem Over a year ago

@Uriel: I just wanted to say the same :)

jsalonen Over a year ago

btw. great answers both!

Uriel · Accepted Answer · 2017-06-25 14:59:46Z

4

>>> print('[{}]'.format(','.join(repr(x) for x in list1)))
['Aena','Cellnex Telecom','Amadeus','Abertis']

answered Jun 25, 2017 at 14:59

Uriel

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