Array to String conversion

Question

here's my code:

$menu .= $this->$item['type']($item);

$item['type'] is a string - 'single' and it uses method single(). Yet the browser shows me this error:

Array to string conversion

I have no idea why, since single returns a string, $item['type'] also is a string. I even tried checking this:

var_dump($this->$item['type']([]));

and it still returns the same error. Do you know why?

did you try to see var_dump($this->$item['type']); it returns what ? — Seifeddine Besbes
– Seifeddine Besbes, Commented Jul 4, 2017 at 22:46
there is one explanation that $item['type'] is an array, perhaps an array contains your string try to see what $item['type'] returns to know for sure — Seifeddine Besbes
– Seifeddine Besbes, Commented Jul 4, 2017 at 22:55
that's the problem, I've tried multiple times and it always returns string(6) "single" — Zbyszek Kisły
– Zbyszek Kisły, Commented Jul 4, 2017 at 22:57

Carsten Massmann · Accepted Answer · 2017-07-04 23:43:41Z

1

You need to wrap the string that was found in the array element in curly brackets before using it as a method name to your object:

$menu .= $this->{$item['type']}($item);

See here: http://php.net/manual/en/language.types.object.php

answered Jul 4, 2017 at 23:43

Carsten Massmann

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2 Comments

Zbyszek Kisły Over a year ago

I'm just curious - did it suppose to work in ealier versions of PHP? I have project that was running php 5.6 and I was working on 7.0 when it stopped working.

Carsten Massmann Over a year ago

Well, honestly, I don't know. But looking at it again, I can understand, why the brackets are needed here. Without them PHP (any version!) would have to "think" that you want to access the function under the $type-th element of the object property $this->$time (assuming $time to be a string!). The curly brackets force PHP to evaluate the term$time[$type] first.

Seifeddine Besbes · Accepted Answer · 2017-07-04 23:33:32Z

1

i believe this will work try it :

$method = $item['type'];
var_dump($this->$method($item));

edited Jul 4, 2017 at 23:33

answered Jul 4, 2017 at 23:12

Seifeddine Besbes

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2 Comments

Zbyszek Kisły Over a year ago

it does and I have no idea why. Care to explain?

Seifeddine Besbes Over a year ago

yes sure, as we know php support variable functions but only simple variable. it does not support array as variable function. php.net/manual/en/functions.variable-functions.php

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