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Globally in a file, I want to find all occurrences of strings starting with .git#v and replace the part of the string from the v until the next " with another string.

So, f.e. if I had migrations.git#v1.1.1", - I want to find it by .git#v and replace v1.1.1 with develop. The point is that the version number will vary for the different occurrences, that's why I need to rely on finding these pieces by the .git#v part.

I've got this so far:

sed -i -- 's/.git#v/.git#develop/g' package.json

but I know this is quite not enough because it will only replace the whole .git#v with develop.

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1 Answer 1

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echo 'migrations.git#v1.1.1"' |sed -r 's/\.git#v[^"]+"/\.git#develop/g'
migrations.git#develop

IF you do not wish to use -r : + sign needs to be taken care of.

sed 's/\.git#v[^"]\+"/\.git#develop/g'
migrations.git#develop

awk solution , using gsub :

echo 'migrations.git#v1.1.1"' |awk '{gsub(/.git#v[^"]+"/,".git#develop")}1'
migrations.git#develop
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8 Comments

Oh, forgot to say I'm on OSX. -r is an illegal option for sed.
@Milkncookiez check update in answer for alternate approch.
I'd use sed 's/\.git#v[^"]\+"/\.git#develop/g' package.json but it would only print the contents of the file, w/o any actions performed on it.
did you tried -E option like sed -E 's/\.git#v[^"]+"/\.git#develop/g' ?
@Milkncookiez echo 'migrations.git#v1.1.1"' | sed 's/\.git#v[^"]*/.git#develop/g' should work with any sed version...
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