function is not invoking in javascript

Question

Can anyone tell what is problem in the following code... when i run the program in browser a blank white screen appears... I don't know why its not working... I am not very sure with the syntax...
I don't want to invoke the function by any events.. i just want to write a function and invoke it by a manual call...

    <html>
    <head>
        <script language="javascript" type="text/javascript">
            function salin()
            {
                var sal = prompt("Enter your current salary - ","");
                var in = prompt("Enter the increment % - ","");

                sal = parseInt(sal);
                in = parseInt(in);

                var nsal = sal +( sal*(in /100));

                alert("Your new salary is - " + nsal);
            }

         salin();
      </script>
    </head>

    <body>
    </body>
    </html>

You must be getting error: "message": "Uncaught SyntaxError: Unexpected token in", — Ved
– Ved, Commented Jul 12, 2017 at 5:09
in is reserved keyword in java-script so, your variable name cannot be in — Atul Sharma
– Atul Sharma, Commented Jul 12, 2017 at 5:09
@trex1999 Where exactly are you looking? In Firefox you get SyntaxError: missing variable name. — Sebastian Simon
– Sebastian Simon, Commented Jul 12, 2017 at 5:23

brk · Accepted Answer · 2017-07-12 05:07:31Z

5

The issue seems to be in this line in = parseInt(in);

in is a reserved keyword in javascript which is use to return a boolean value. Replace it with a different variable name

answered Jul 12, 2017 at 5:07

brk

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Comments

Syed Abdur Rehman Kazmi · Accepted Answer · 2017-07-12 05:36:20Z

3

I have created this fiddle..

Its working. You were using reserved javascript keyword

function salin()
            {
                var sal = prompt("Enter your current salary - ","");
                var values = prompt("Enter the increment % - ","");

                sal = parseInt(sal);
                values = parseInt(values);

                var nsal = sal +( sal*(values /100));

                alert("Your new salary is - " + nsal);
            }

         salin();

https://jsfiddle.net/abdur_rehman26/7L9uvxon/

answered Jul 12, 2017 at 5:36

Syed Abdur Rehman Kazmi

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Comments

Difster · Accepted Answer · 2017-07-12 05:10:21Z

0

Try this instead:

function salin()
        {

                            var sal = prompt("Enter your current salary - ","");
            var income = prompt("Enter the increment % - ","");

            sal = parseInt(sal);
            income = parseInt(income);

            var nsal = sal +( sal*(income /100));

            return "Your new salary is - " + nsal;
        }

     alert(salin());

Notice I added return and put the alert() on the function call. I also changed "in" to "income"

answered Jul 12, 2017 at 5:10

Difster

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1 Comment

Sebastian Simon Over a year ago

Good answers don’t just dump “working” code. Good answers explain the OP’s mistake or how to approach the problem.

Nitu Bansal · Accepted Answer · 2017-07-12 05:17:18Z

0

'in' is a reserved keyword. change that to some other variable name

       <body>

    <script language="javascript" type="text/javascript">
        function salin()
        {
            var sal = prompt("Enter your current salary - ","");
            var in1 = prompt("Enter the increment % - ","");

            sal = parseInt(sal);
            in1 = parseInt(in1);

            var nsal = sal +( sal*(in1 /100));

            alert("Your new salary is - " + nsal);
        }

     salin();
  </script>



</body>

answered Jul 12, 2017 at 5:17

Nitu Bansal

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