How to use the array passed in the constructor

Question

I am confused about constructor. I need to pass an array to a class. I have at the moment 2 data to pass to the array.

Now from this array, I need to define $this->m_id and $this->community_type so that I can use these variables through out the class. Below is my example.

$arr = array('id'=>$u_id, 'community_type' => $community_type);
$rate = new Registration($arr);

class Registration{
    protected $m_id;
    protected $community_type;

    public function __construct(array $arr = array())
    {
        foreach ($arr as $key => $value) {
            $this->$key = $value;
        }
    }
}

I am looking to set

$this->m_id = $m_id;
$this->community_type = $community_type;

I tried using a for loop but I don't know something went wrong. Can anybody help me

outside of the class, $rate->id and $rate->community_type — Scuzzy
– Scuzzy, Commented Jul 21, 2017 at 3:47
Actually, you're going to run into issues with that community_type being set as protected, I missed that sorry. Wait for a full answer. — Scuzzy
– Scuzzy, Commented Jul 21, 2017 at 3:52

Ravi · Accepted Answer · 2017-07-21 04:02:54Z

1

You could try $array[your_array_key] as follow

public function __construct(array $arr = array())
{
    $this->m_id = $arr['id'];
    $this->community_type = $arr['community_type'];
}

Your existing code should work, if you are trying through loop, only problem I could notice is,

  protected $m_id;

You need to change this to

 protected $id;

Because, in your loop you are assuming your key is the member variable, which is actually not.

   foreach ($arr as $key => $value) {
        $this->$key = $value;
    }

In you are array, your first key is id where as member variable declared as m_id, which is not matching.

edited Jul 21, 2017 at 4:02

answered Jul 21, 2017 at 3:56

Ravi

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2 Comments

S S Over a year ago

i just include 2 items in the array but lets say i have many then what can i do

Ravi Over a year ago

then you could loop it through. I will update the answer.

Tim Morton · Accepted Answer · 2017-07-21 04:14:56Z

When run in the terminal, it shows that the object's properties are being created dynamically exactly as one would expect:

php > class Registration{
php {     protected $m_id;
php {     protected $community_type;
php { 
php {     public function __construct(array $arr = array())
php {     {
php {         foreach ($arr as $key => $value) {
php {             $this->$key = $value;
php {         }
php {     }
php { }
php > $u_id = 'u_id value';
php > $community_type = 'community type value';
php > 
php > $arr = array('id'=>$u_id, 'community_type' => $community_type);
php > $rate = new Registration($arr);
php > 
php > var_dump($rate);
object(Registration)#1 (3) {
  ["m_id":protected]=>
  NULL
  ["community_type":protected]=>
  string(20) "community type value"
  ["id"]=>
  string(10) "u_id value"
}

I think there were several confounding factors that may have tripped you up:

Were the $u_id and $community_type variables assigned? They weren't in your code.
There was some confusion about the variable names: $m_id vs $u_id, ['id'] vs $this->m_id
Protected makes them harder access.

The var_dump shows that the keys of your array (['id'] and ['community_type'] were indeed assigned as properties of the object.

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