Let's say I have an array
A=[1 2 3 2 4 5 6]
Now i need to store first 3 values of array A into array B
I am doing
b.append(a[1])
b.append(a[2])
b.append(a[3])
but I am unable to get any output.
3 Answers
You should consider to use slices
a = [1, 2, 3, 4, 5]
b = a[:3]
print b #print(b) for Python 3.x
Output:
[1, 2, 3]
3 Comments
dheiberg
A slightly better (imo) resource would be: pythoncentral.io/how-to-slice-listsarrays-and-tuples-in-python
user123456789
ok this is fine but if u want element 2,3,4 in new list then how to do that??
Igor Kurilko
b = a[1:4], you should really read about that slicing stuff, it's awesome :-)
You don't even have to declare a second empty list.
a = [1,2,3,4,5]
b = list(a[:3])
Comments
Input list
a = [1, 2, 3, 4, 5, 6]
print a
Output list (using slides)
b = a[:3]
print b
Output list (taking desired elements)
b = [a[0], a[1], a[2]]
print b
Output list (appending desired elements)
b = []
b.append(a[0])
b.append(a[1])
b.append(a[2])
print b
b = a[:3]. Also, what do you mean by not getting any output?print(b)give you? And what do you expect to see?