I have an array that looks like this, how can I sort it alphabetically without loosing the key?
var items = [
{ 11: 'Edward' },
{ 12: 'Sharpe' },
{ 13: 'Alvin' }
];
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1Does all object have only 1 key-value pair?ibrahim mahrir– ibrahim mahrir2017-08-24 22:21:16 +00:00Commented Aug 24, 2017 at 22:21
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yes, numbers are keys, and names are values..Gibran Ibrahim– Gibran Ibrahim2017-08-24 22:57:47 +00:00Commented Aug 24, 2017 at 22:57
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3 Answers
You can sort the items array using Object.values.
const items = [
{ 11: 'Edward' },
{ 12: 'Sharpe' },
{ 13: 'Alvin' }
];
items.sort((a, b) => Object.values(a)[0] > Object.values(b)[0]);
console.log(items);1 Comment
Mouser
Nice solution, will fail though on
Internet Explorer.If the objects have only one key, then you can use Object.keys to retrieve that key an then sort:
var items = [
{ '11': 'Edward' },
{ '12': 'Sharpe' },
{ '13': 'Alvin' }
];
items.sort(function(a, b) {
var akey = Object.keys(a) [0], // get a's key
bkey = Object.keys(b) [0]; // get b's key
return a[akey].localeCompare(b[bkey]); // compare the values using those keys
});
console.log(items);
Comments
By using Object.keys, since they only have one value we don't know, we can use the length property minus one to get the actual key reference.
var items = [
{ 11: 'Edward' },
{ 12: 'Sharpe' },
{ 13: 'Alvin' }
];
items.sort(function(a, b){
var c = Object.keys(a);
var d = Object.keys(b);
return a[c[c.length-1]] > b[d[d.length-1]] ? 1: -1;
}
)
console.log(items);