Convert string to number in typescript without losing leading zero without using an array solution

Question

I need to split a string of numbers and convert to number. converted strings must not reduced or something. For example when i use to convert "01" in string to 01 in number like below, i got something wrong. For example i have this string "0601",

var _stringNumber = '0601';
var _number = Number('0601'); // result is 601

i need _number = 0601 but result is 601.

what is the solution?

It's the way numbers work since they discovered them centuries ago. — ibrahim mahrir
– ibrahim mahrir, Commented Sep 15, 2017 at 19:02
Then you just set the numbers, if it expects each property to actually be a number it is not going to expect a leading 0. — Patrick Evans
– Patrick Evans, Commented Sep 15, 2017 at 19:08
Classic XY Problem — you asked how to keep the leading zero but that was your own proposed solution to your real problem: how can you init your ngbCalendar. You should delete this question and ask a new one for what you are actually trying to do. — Stephen P
– Stephen P, Commented Sep 15, 2017 at 19:09

Ryan Cavanaugh · Accepted Answer · 2017-09-15 19:00:03Z

4

A number is a number; there is no way to distinguish 3 from 03 because these are the same number.

answered Sep 15, 2017 at 19:00

Ryan Cavanaugh

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Septian · Accepted Answer · 2022-04-09 05:54:04Z

0

You can use simple for loop

let stringNumber = '0601';
let tempNumbers = [];

for(let i = 0; i < stringNumber.length; i++) {
   tempNumbers.push(+stringNumber[i]);
}

let number = tempNumbers.join('');

// Result : 0601

answered Apr 9, 2022 at 5:54

Septian

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Comments

Jimenemex · Accepted Answer · 2017-09-15 19:18:35Z

-1

Make an Object

var MyNumber = function(stringNum) {
    var visualNumber = stringNum;
    var actualNumber = Number(visualNumber);
}

Usage:

var num = MyNumber('0601');
var dummyNum = 65;
var resultNum = dummyNum + num.actualNumber;
console.log(resultNum); // 666... (O.o) <- Oh noes

answered Sep 15, 2017 at 19:18

Jimenemex

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