calling a function in a named namespace from anonymous namespace

Question

In a file there is an anonymous namespace and a named namespace. Anonymous namespace has some internal function which should not be exposed and the named namespace has some overloaded functions which need to be accessed.

//test.cpp

namespace
{
void func() {}
void crazy()
{
   func(a);
}
}

namespace useful
{
void func(int a)
{
    //something
}
}

Can someone suggest me how to access a named namespace which is written below it ? Is it okay to access a function of a named namespace from an anonymous namespace ?

The function ::crazy() needs to be defined AFTER a declaration of useful::func(), not before. — Peter
– Peter, Commented Sep 17, 2017 at 1:15

wally · Accepted Answer · 2017-09-17 01:16:36Z

1

You can declare in the relevant namespace before it is used and defined:

//test.cpp

namespace useful {
void func(int);
}

namespace
{
void func() {}
void crazy()
{
    useful::func(3);
}
}

namespace useful
{
void func(int a)
{
    //something
}
}

answered Sep 17, 2017 at 1:16

wally

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