Sort an array of array by 2 conditions

Question

I have to sort this

ary = [[5, "e", "2"], [2, "r", "="], [2, "y", "2"], [2, "h", "="]]

to obtain :

# => [[5, "e", "2"], [2, "y", "2"], [2, "h", "="], [2, "r", "="]]

If the last element (index 2) is equal to "=" it must be after the array which has the same first element even if the letter is before. Something like this :

ary.each_with_index do |array, index|
  if ary[index][2] == "=" && ary[index][0] == ary[index +1][2]
    a = ary[index]
    b = ary[index +1]
    ary[index] = b
    ary[index+1] = a
  end
end

Looking at the elements with "=", do you want to sort in decreasing order on the first element? When there are ties, sort in increasing order of the second element? Same for elements without "="? What aboutary = [[2, "e", "2"], [2, "e", "10"]]? Please clarify by editing (rather than posting a comment). — Cary Swoveland
– Cary Swoveland, Commented Sep 28, 2017 at 20:31

Cary Swoveland · Accepted Answer · 2017-09-29 16:53:10Z

2

I assume that, for elements ending with "=", sorting is by decreasing value of the first element (integers) and when there are ties, by increasing order of the second element (strings). Further, I assume sorting is the same for elements not ending with "=", except when the first two elements both tie, sorting is by increasing order of the last element (strings).

def sort_em(arr)
  arr.sort_by { |n, s1, s2| [s2 == "=" ? 1 : 0, -n, s1, s2] }
end

sort_em [[5, "e", "2"], [2, "r", "="], [2, "y", "2"], [2, "h", "="]]
  #=> [[5, "e", "2"], [2, "y", "2"], [2, "h", "="], [2, "r", "="]]

See the third paragraph of the doc for Array#<=> for an explanation of how arrays are ordered when sorting.

To ensure elements ending with "=" come last in the sort, I've simply added 1 (0) at the beginning of array in sort_by's block for arrays ending (not ending) with "=".

edited Sep 29, 2017 at 16:53

answered Sep 28, 2017 at 21:02

Cary Swoveland

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Comments

ulferts · Accepted Answer · 2017-09-28 21:50:44Z

1

You can use sort and provide your own block for sorting:

ary.sort do |a, b| 
  if a[2] == '=' && b[2] != '='
    # a has '=' => a > b 
    1
  elsif b[2] == '=' && a[2] != '='
    # b has '=' => a < b 
    -1
  else
    # This is hit if neither a nor b have a '=' OR when both do.
    # Use default comparison operator
    # but restrict it to the second element of the array
    a[1] <=> b[1]
  end
end

The block needs to return a value that is 1, -1 or 0. Based on this, the values are placed in order.

1: a > b
-1: a < b
0: a = b

edited Sep 28, 2017 at 21:50

answered Sep 28, 2017 at 20:09

ulferts

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