Python strings and int

Question

I've been following an online course and I've ran into a road block. I wanted to try to see if a list of integers is greater than one given integer. I keep getting the error TypeError: '>=' not supported between instances of 'list' and 'int'. Help?

Here's my attempt:

    def numCount(someList, comparison):
        returnVal = []
        if numList >= comparison:
                returnVal += numList
        return returnVal

    numList=[0, 2, 4, 5, 10]
    print(numCount(someList, 9))

numList is a list right now, and comparison is an int - do you know how to get an int out of the list numList? — FCo
– FCo, Commented Oct 2, 2017 at 2:32
You seem to be mixing up your variables, did you mean print(numCount(numList, 9)) and if someList >= comparison:. Note: You can do this with filter(), e.g. return list(filter(lambda x: x >= comparison, someList)) — AChampion
– AChampion, Commented Oct 2, 2017 at 2:37

Reblochon Masque · Accepted Answer · 2017-10-02 02:33:33Z

1

You must iterate over each item in the list and compare them:

def numCount(someList, comparison):
    returnVal = []
    for elt in someList:
        if elt >= comparison:
            returnVal.append(elt)
    return returnVal

numList=[0, 2, 4, 5, 10]
print(numCount(numList, 9))

output:

[10]

The output is a list of the values in numListthat are greater or equal to the comparison integer.

answered Oct 2, 2017 at 2:33

Reblochon Masque

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1 Comment

isedbrrr Over a year ago

Thank you, sir. As a beginner, this helped me greatly. Upvoted^

JoyStickFanatic · Accepted Answer · 2017-10-02 02:31:29Z

0

Python does not support comparing a list to an int mainly because it doesnt make sense. Do you mean you want to see if the sum of a list of ints is larger than a given int? Or do you want to find all ints in a list that are larger than a given number and return a list containing those ints?

answered Oct 2, 2017 at 2:31

JoyStickFanatic

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